A 2000w 12v pure sine wave inverter draws power based only on its load. Current (Amps) = Load Watts ÷ (Battery Voltage x Inverter Efficiency) Inverter efficiency is typically 85% (0.85). Example (12V system):
A 1500 watt inverter with a 500 watt load would be 50 (25) Amps, not 150 (75) Amps. The same inverter with a 1200 watt load would draw 120 (60) Amps, which would be the same amount as a 1200 watt inverter at load capacity. A 2000w 12v pure sine wave inverter draws power based only on its load.
Inverter Current = Power ÷ Voltage Where: If you’re working with kilowatts (kW), convert it to watts before calculation: Inverter Current = 1000 ÷ 12 = 83.33 Amps So, the inverter draws 83.33 amps from a 12V battery. Inverter Current = 3000 ÷ 24 = 125 Amps So, a 3000W inverter on a 24V system pulls 125 amps from the battery.
The same inverter with a 1200 watt load would draw 120 (60) Amps, which would be the same amount as a 1200 watt inverter at load capacity. A 2000w 12v pure sine wave inverter draws power based only on its load. Current (Amps) = Load Watts ÷ (Battery Voltage x Inverter Efficiency) Inverter efficiency is typically 85% (0.85).
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